6大核心模块(Modules)
示例(Examples)
SQL 数据库(SQL Database)

LangChain

SQL数据库

这篇教程展示了一个代理,它旨在与SQL数据库进行交互。该代理基于SQLDatabaseChain (opens in a new tab)并旨在回答有关数据库的更一般的问题,以及从错误中恢复。

请注意,由于此代理正在积极开发中,因此可能并非所有答案都是正确的。此外,无法保证代理不会针对某些问题在您的数据库上执行DML语句。在敏感数据上运行时,请小心!

这里使用了示例Chinook数据库。要设置它,请按照https://database.guide/2-sample-databases-sqlite/上的说明操作, (opens in a new tab)

将.db文件放在存储库根目录中的notebooks文件夹中。

初始化

from langchain.agents import create_sql_agent
from langchain.agents.agent_toolkits import SQLDatabaseToolkit
from langchain.sql_database import SQLDatabase
from langchain.llms.openai import OpenAI
from langchain.agents import AgentExecutor
 
db = SQLDatabase.from_uri("sqlite:///../../../../notebooks/Chinook.db")
toolkit = SQLDatabaseToolkit(db=db)
 
agent_executor = create_sql_agent(
    llm=OpenAI(temperature=0),
    toolkit=toolkit,
    verbose=True
)
 

示例:描述一个表

agent_executor.run("Describe the playlisttrack table")
 
> Entering new AgentExecutor chain...
Action: list_tables_sql_db
Action Input: ""
Observation: Artist, Invoice, Playlist, Genre, Album, PlaylistTrack, Track, InvoiceLine, MediaType, Employee, Customer
Thought: I should look at the schema of the playlisttrack table
Action: schema_sql_db
Action Input: "PlaylistTrack"
Observation: 
CREATE TABLE "PlaylistTrack" (
 "PlaylistId" INTEGER NOT NULL, 
 "TrackId" INTEGER NOT NULL, 
 PRIMARY KEY ("PlaylistId", "TrackId"), 
 FOREIGN KEY("TrackId") REFERENCES "Track" ("TrackId"), 
 FOREIGN KEY("PlaylistId") REFERENCES "Playlist" ("PlaylistId")
)
 
SELECT * FROM 'PlaylistTrack' LIMIT 3;
PlaylistId TrackId
1 3402
1 3389
1 3390
Thought: I now know the final answer
Final Answer: The PlaylistTrack table has two columns, PlaylistId and TrackId, and is linked to the Playlist and Track tables.
 
> Finished chain.
 
'The PlaylistTrack table has two columns, PlaylistId and TrackId, and is linked to the Playlist and Track tables.'

示例:描述一张表,从错误中恢复

from langchain.agents import create_sql_agent
from langchain.agents.agent_toolkits import SQLDatabaseToolkit
from langchain.sql_database import SQLDatabase
from langchain.llms.openai import OpenAI
from langchain.agents import AgentExecutor
 
db = SQLDatabase.from_uri("sqlite:///../../../../notebooks/Chinook.db")
toolkit = SQLDatabaseToolkit(db=db)
 
agent_executor = create_sql_agent(
    llm=OpenAI(temperature=0),
    toolkit=toolkit,
    verbose=True
)
 

例子:运行查询#

agent_executor.run("List the total sales per country. Which country's customers spent the most?")
 
> Entering new AgentExecutor chain...
Action: list_tables_sql_db
Action Input: ""
Observation: Invoice, MediaType, Artist, InvoiceLine, Genre, Playlist, Employee, Album, PlaylistTrack, Track, Customer
Thought: I should look at the schema of the relevant tables to see what columns I can use.
Action: schema_sql_db
Action Input: "Invoice, Customer"
Observation: 
CREATE TABLE "Customer" (
 "CustomerId" INTEGER NOT NULL, 
 "FirstName" NVARCHAR(40) NOT NULL, 
 "LastName" NVARCHAR(20) NOT NULL, 
 "Company" NVARCHAR(80), 
 "Address" NVARCHAR(70), 
 "City" NVARCHAR(40), 
 "State" NVARCHAR(40), 
 "Country" NVARCHAR(40), 
 "PostalCode" NVARCHAR(10), 
 "Phone" NVARCHAR(24), 
 "Fax" NVARCHAR(24), 
 "Email" NVARCHAR(60) NOT NULL, 
 "SupportRepId" INTEGER, 
 PRIMARY KEY ("CustomerId"), 
 FOREIGN KEY("SupportRepId") REFERENCES "Employee" ("EmployeeId")
)
 
SELECT * FROM 'Customer' LIMIT 3;
CustomerId FirstName LastName Company Address City State Country PostalCode Phone Fax Email SupportRepId
1 Luís Gonçalves Embraer - Empresa Brasileira de Aeronáutica S.A. Av. Brigadeiro Faria Lima, 2170 São José dos Campos SP Brazil 12227-000 +55 (12) 3923-5555 +55 (12) 3923-5566 luisg@embraer.com.br 3
2 Leonie Köhler None Theodor-Heuss-Straße 34 Stuttgart None Germany 70174 +49 0711 2842222 None leonekohler@surfeu.de 5
3 François Tremblay None 1498 rue Bélanger Montréal QC Canada H2G 1A7 +1 (514) 721-4711 None ftremblay@gmail.com 3
 
CREATE TABLE "Invoice" (
 "InvoiceId" INTEGER NOT NULL, 
 "CustomerId" INTEGER NOT NULL, 
 "InvoiceDate" DATETIME NOT NULL, 
 "BillingAddress" NVARCHAR(70), 
 "BillingCity" NVARCHAR(40), 
 "BillingState" NVARCHAR(40), 
 "BillingCountry" NVARCHAR(40), 
 "BillingPostalCode" NVARCHAR(10), 
 "Total" NUMERIC(10, 2) NOT NULL, 
 PRIMARY KEY ("InvoiceId"), 
 FOREIGN KEY("CustomerId") REFERENCES "Customer" ("CustomerId")
)
 
SELECT * FROM 'Invoice' LIMIT 3;
InvoiceId CustomerId InvoiceDate BillingAddress BillingCity BillingState BillingCountry BillingPostalCode Total
1 2 2009-01-01 00:00:00 Theodor-Heuss-Straße 34 Stuttgart None Germany 70174 1.98
2 4 2009-01-02 00:00:00 Ullevålsveien 14 Oslo None Norway 0171 3.96
3 8 2009-01-03 00:00:00 Grétrystraat 63 Brussels None Belgium 1000 5.94
Thought: I should query the Invoice and Customer tables to get the total sales per country.
Action: query_sql_db
Action Input: SELECT c.Country, SUM(i.Total) AS TotalSales FROM Invoice i INNER JOIN Customer c ON i.CustomerId = c.CustomerId GROUP BY c.Country ORDER BY TotalSales DESC LIMIT 10
Observation: [('USA', 523.0600000000003), ('Canada', 303.9599999999999), ('France', 195.09999999999994), ('Brazil', 190.09999999999997), ('Germany', 156.48), ('United Kingdom', 112.85999999999999), ('Czech Republic', 90.24000000000001), ('Portugal', 77.23999999999998), ('India', 75.25999999999999), ('Chile', 46.62)]
Thought: I now know the final answer
Final Answer: The customers from the USA spent the most, with a total of $523.06.
 
> Finished chain.
 
'The customers from the USA spent the most, with a total of $523.06.'
 
agent_executor.run("Show the total number of tracks in each playlist. The Playlist name should be included in the result.")
 
> Entering new AgentExecutor chain...
Action: list_tables_sql_db
Action Input: ""
Observation: Invoice, MediaType, Artist, InvoiceLine, Genre, Playlist, Employee, Album, PlaylistTrack, Track, Customer
Thought: I should look at the schema of the Playlist and PlaylistTrack tables to see what columns I can use.
Action: schema_sql_db
Action Input: "Playlist, PlaylistTrack"
Observation: 
CREATE TABLE "Playlist" (
 "PlaylistId" INTEGER NOT NULL, 
 "Name" NVARCHAR(120), 
 PRIMARY KEY ("PlaylistId")
)
 
SELECT * FROM 'Playlist' LIMIT 3;
PlaylistId Name
1 Music
2 Movies
3 TV Shows
 
CREATE TABLE "PlaylistTrack" (
 "PlaylistId" INTEGER NOT NULL, 
 "TrackId" INTEGER NOT NULL, 
 PRIMARY KEY ("PlaylistId", "TrackId"), 
 FOREIGN KEY("TrackId") REFERENCES "Track" ("TrackId"), 
 FOREIGN KEY("PlaylistId") REFERENCES "Playlist" ("PlaylistId")
)
 
SELECT * FROM 'PlaylistTrack' LIMIT 3;
PlaylistId TrackId
1 3402
1 3389
1 3390
Thought: I can use a SELECT statement to get the total number of tracks in each playlist.
Action: query_checker_sql_db
Action Input: SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name
Observation: 
 
SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name
Thought: The query looks correct, I can now execute it.
Action: query_sql_db
Action Input: SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name LIMIT 10
Observation: [('90’s Music', 1477), ('Brazilian Music', 39), ('Classical', 75), ('Classical 101 - Deep Cuts', 25), ('Classical 101 - Next Steps', 25), ('Classical 101 - The Basics', 25), ('Grunge', 15), ('Heavy Metal Classic', 26), ('Music', 6580), ('Music Videos', 1)]
Thought: I now know the final answer.
Final Answer: The total number of tracks in each playlist are: '90’s Music' (1477), 'Brazilian Music' (39), 'Classical' (75), 'Classical 101 - Deep Cuts' (25), 'Classical 101 - Next Steps' (25), 'Classical 101 - The Basics' (25), 'Grunge' (15), 'Heavy Metal Classic' (26), 'Music' (6580), 'Music Videos' (1).
 
> Finished chain.
 
"The total number of tracks in each playlist are: '90’s Music' (1477), 'Brazilian Music' (39), 'Classical' (75), 'Classical 101 - Deep Cuts' (25), 'Classical 101 - Next Steps' (25), 'Classical 101 - The Basics' (25), 'Grunge' (15), 'Heavy Metal Classic' (26), 'Music' (6580), 'Music Videos' (1)."
 

从错误中恢复#

在这个例子中,代理最初尝试访问一个不存在的属性 (Track.ArtistId), 但能够从错误中恢复。

agent_executor.run("Who are the top 3 best selling artists?")
 
> Entering new AgentExecutor chain...
Action: list_tables_sql_db
Action Input: ""
Observation: MediaType, Track, Invoice, Album, Playlist, Customer, Employee, InvoiceLine, PlaylistTrack, Genre, Artist
Thought: I should look at the schema of the Artist, InvoiceLine, and Track tables to see what columns I can use.
Action: schema_sql_db
Action Input: "Artist, InvoiceLine, Track"
Observation: 
CREATE TABLE "Artist" (
 "ArtistId" INTEGER NOT NULL, 
 "Name" NVARCHAR(120), 
 PRIMARY KEY ("ArtistId")
)
 
SELECT * FROM 'Artist' LIMIT 3;
ArtistId Name
1 AC/DC
2 Accept
3 Aerosmith
 
CREATE TABLE "Track" (
 "TrackId" INTEGER NOT NULL, 
 "Name" NVARCHAR(200) NOT NULL, 
 "AlbumId" INTEGER, 
 "MediaTypeId" INTEGER NOT NULL, 
 "GenreId" INTEGER, 
 "Composer" NVARCHAR(220), 
 "Milliseconds" INTEGER NOT NULL, 
 "Bytes" INTEGER, 
 "UnitPrice" NUMERIC(10, 2) NOT NULL, 
 PRIMARY KEY ("TrackId"), 
 FOREIGN KEY("MediaTypeId") REFERENCES "MediaType" ("MediaTypeId"), 
 FOREIGN KEY("GenreId") REFERENCES "Genre" ("GenreId"), 
 FOREIGN KEY("AlbumId") REFERENCES "Album" ("AlbumId")
)
 
SELECT * FROM 'Track' LIMIT 3;
TrackId Name AlbumId MediaTypeId GenreId Composer Milliseconds Bytes UnitPrice
1 For Those About To Rock (We Salute You) 1 1 1 Angus Young, Malcolm Young, Brian Johnson 343719 11170334 0.99
2 Balls to the Wall 2 2 1 None 342562 5510424 0.99
3 Fast As a Shark 3 2 1 F. Baltes, S. Kaufman, U. Dirkscneider & W. Hoffman 230619 3990994 0.99
 
CREATE TABLE "InvoiceLine" (
 "InvoiceLineId" INTEGER NOT NULL, 
 "InvoiceId" INTEGER NOT NULL, 
 "TrackId" INTEGER NOT NULL, 
 "UnitPrice" NUMERIC(10, 2) NOT NULL, 
 "Quantity" INTEGER NOT NULL, 
 PRIMARY KEY ("InvoiceLineId"), 
 FOREIGN KEY("TrackId") REFERENCES "Track" ("TrackId"), 
 FOREIGN KEY("InvoiceId") REFERENCES "Invoice" ("InvoiceId")
)
 
SELECT * FROM 'InvoiceLine' LIMIT 3;
InvoiceLineId InvoiceId TrackId UnitPrice Quantity
1 1 2 0.99 1
2 1 4 0.99 1
3 2 6 0.99 1
Thought: I should query the database to get the top 3 best selling artists.
Action: query_sql_db
Action Input: SELECT Artist.Name, SUM(InvoiceLine.Quantity) AS TotalQuantity FROM Artist INNER JOIN Track ON Artist.ArtistId = Track.ArtistId INNER JOIN InvoiceLine ON Track.TrackId = InvoiceLine.TrackId GROUP BY Artist.Name ORDER BY TotalQuantity DESC LIMIT 3
Observation: Error: (sqlite3.OperationalError) no such column: Track.ArtistId
[SQL: SELECT Artist.Name, SUM(InvoiceLine.Quantity) AS TotalQuantity FROM Artist INNER JOIN Track ON Artist.ArtistId = Track.ArtistId INNER JOIN InvoiceLine ON Track.TrackId = InvoiceLine.TrackId GROUP BY Artist.Name ORDER BY TotalQuantity DESC LIMIT 3]
(Background on this error at: https://sqlalche.me/e/14/e3q8)
Thought: I should double check my query before executing it.
Action: query_checker_sql_db
Action Input: SELECT Artist.Name, SUM(InvoiceLine.Quantity) AS TotalQuantity FROM Artist INNER JOIN Track ON Artist.ArtistId = Track.ArtistId INNER JOIN InvoiceLine ON Track.TrackId = InvoiceLine.TrackId GROUP BY Artist.Name ORDER BY TotalQuantity DESC LIMIT 3
Observation: 
 
SELECT Artist.Name, SUM(InvoiceLine.Quantity) AS TotalQuantity 
FROM Artist 
INNER JOIN Track ON Artist.ArtistId = Track.ArtistId 
INNER JOIN InvoiceLine ON Track.TrackId = InvoiceLine.TrackId 
GROUP BY Artist.Name 
ORDER BY TotalQuantity DESC 
LIMIT 3;
Thought: I now know the final answer.
Action: query_sql_db
Action Input: SELECT Artist.Name, SUM(InvoiceLine.Quantity) AS TotalQuantity FROM Artist INNER JOIN Album ON Artist.ArtistId = Album.ArtistId INNER JOIN Track ON Album.AlbumId = Track.AlbumId INNER JOIN InvoiceLine ON Track.TrackId = InvoiceLine.TrackId GROUP BY Artist.Name ORDER BY TotalQuantity DESC LIMIT 3
Observation: [('Iron Maiden', 140), ('U2', 107), ('Metallica', 91)]
Thought: I now know the final answer.
Final Answer: The top 3 best selling artists are Iron Maiden, U2, and Metallica.
 
> Finished chain.
 
'The top 3 best selling artists are Iron Maiden, U2, and Metallica.'